.Chemical.Processes.Internal.Kinetics.traditionalPotentialDiff

Information

This Gibbs energy loss du to reach chemical process molar flow q:

 = kf * xA - kb * xB

where kf is the forwar rate coefficient and kb is backward rate coefficient of chemical process; xA is mole fraction os substrate and xB is mole fraction of product. And K = kf/kb = xB/xA is a dissociation coefficient of the chemical process.

Interface

function traditionalPotentialDiff
  extends partialPotentialDiff;
end traditionalPotentialDiff;