Integrator circuit vs QAG integration routine.
input voltage: V0 (1 - e-t/τ1) e-t/τ2
The recalculation of the integral via QAG for each time t is a bit of overkill, but the agreement with the output voltage from the integrator circuit is thereby made clear. The slight difference is due to a combination of the finite timestep for the circuit simulation, the op-amp's behavior, and the relative error in the QAG integrator.
IMPORTANT!!!: The integrand-setup model 'CircuitIntegrand' (or a duplicate) must be run before using GSL integration routines within a larger Modelica model (like this one). (Alternatively, one could edit integrand.c directly and then compile "by hand" in a command window: gcc -fPIC -c integrand.c integration_mi.c
gcc -shared integration.o integration_mi.o -o libgsl_integration_MI.so [.dll for windows])
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.GNU_ScientificLibrary.Examples.integration.IntegratingCircuit.IntegratingCircuit
CircuitParams