.Modelica.Math.Special.erfc

Information

Syntax

Special.erfc(u);

Description

This function computes the complementary error function erfc(u) = 1 - erf(u) with a relative precision of about 1e-15. The implementation utilizes the formulation of the Boost library (53-bit implementation of erf.hpp developed by John Maddock). Plot of the function:

If u is large and erf(u) is subtracted from 1.0, the result is not accurate. It is then better to use erfc(u). For more details, see Wikipedia.

Example

erfc(0)    // = 1
erfc(10)   // = 0
erfc(0.5)  // = 0.4795001221869534

See also

erf, erfInv, erfcInv.

Interface

function erfc
  extends Modelica.Icons.Function;
  input Real u "Input argument";
  output Real y "= 1 - erf(u)";
end erfc;

Revisions

Date	Description
June 22, 2015	Initial version implemented by A. Klöckner, F. v.d. Linden, D. Zimmer, M. Otter. DLR Institute of System Dynamics and Control