.PowerGrids.Electrical.Test.TwoBusesResistiveTransmissionLineFault

Information

This model demonstrates the behaviour of a purely resistive transmission line with a purely resistive intermediate fault.

At the beginning of the transient, a current flows from bus A (phase to phase voltage 10 kV) to bus B (phase-to-phase voltage 9 kV) through a resistance of 1 Ohm.

As a consequence, the current flowing in each conductor is

I = (VA - VB)/R = ((UA-UB)/sqrt3)/R = 577.35 A.

When the fault is activated, the analytical computation of the current flowing into the fault yields a current of 10.5215 kA, which corresponds to the simulation result.

At time = 0.6 the fault is cleared and the current through the line returns to the original value.