The example contains experimental data from a real district heating network.
This model compares the results with the original Modelica Standard Library pipes.
The pipes' temperatures are not initialized. Therefore, results of outflow temperature before approximately the first 10000 seconds should not be considered.
There are some uncertainties about the heat loss coefficient between pipe and
surrounding air as well as regarding the heat conductivity of the insulation
material.
With the
given data, the length specific thermal resistance is R = 2.164
((m K)/W), calculated as follows:
R=((1/(2*pipe.kIns)*log((0.0603+2*pipe.dIns)/(0.0603)))+1/(5*(0.0603+2*pipe.dIns)))/Modelica.Constants.pi
U = 1/R = 0.462 W/(m K)
Name | Description |
---|---|
Medium |