.Modelica.Math.FastFourierTransform.Examples.RealFFT1

Information

In this example the signal y

y = 5 + 3*sin(2*pi*f1) + 1.5*cos(2*pi*f2)

is sampled and an FFT is computed from the sampled signal (default: f1 = 2 Hz, f2 = 3 Hz). In the public part the FFT is stored up to f_max (internally in the protected part the FFT is stored up to 5*f_max). With the default values for f_max (= 4 Hz) and f_resolution (= 0.2 Hz), the following results are achieved:

fi[0]  = 0,  Ai[0]  = 5;   // mean value of signal
fi[11] = 2,  Ai[11] = 3;   // frequency/amplitude of sine
fi[16] = 3,  Ai[16] = 1.5; // frequency/amplitude of cosine

A plot of the resulting FFT is shown in the next image:

Note, phases of small amplitudes (= smaller as 0.0001*maximalAmplitude) are explicitly set to zero, since the corresponding "phase" is numerical noise (and would just be confusing). Furthermore, note that the FFT phases are with respect to a cos(..) signal.

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