.Modelica.Thermal.FluidHeatFlow.Examples.ParallelCooling .Modelica.Thermal.FluidHeatFlow.Examples.ParallelCooling2nd test example: ParallelCooling
Two prescribed heat sources dissipate their heat through thermal conductors to coolant flows. The coolant flow is taken from an ambient and driven by a pump with prescribed mass flow, then split into two coolant flows connected to the two heat sources, and afterwards merged. Splitting of coolant flows is determined by pressure drop characteristic of the two pipes.| output | explanation | formula | actual steady-state value |
| dTSource1 | Temperature difference between heat source 1 and ambient condition | dTCoolant1 + dTtoPipe1 | 15 K |
| dTtoPipe1 | Temperature difference between heat source 1 and coolant in pipe 1 | Losses1 / ThermalConductor1.G | 5 K |
| dTCoolant1 | Coolant1's temperature increase in pipe 1 | Losses * cp * totalMassFlow/2 | 10 K |
| dTSource2 | Temperature difference between heat source 2 and ambient condition | dTCoolant2 + dTtoPipe2 | 30 K |
| dTtoPipe2 | Temperature difference between heat source 2 and coolant in pipe 2 | Losses2 / ThermalConductor2.G | 10 K |
| dTCoolant2 | Coolant2's temperature increase in pipe 2 | Losses * cp * totalMassFlow/2 | 20 K |
| dTmixedCoolant | Mixed coolant's temperature increase | (dTCoolant1+dTCoolant2)/2 | 15 K |