functionnormalizationFactor
Compute correction factor of low pass filter such that amplitude at cut-off frequency is -3db (=10^(-3/20) = 0.70794...)
Inputs
| Type | Name | Default | Description |
|---|---|---|---|
| Real[:] | c1 | [p] coefficients of denominator polynomials (c1[i}*p + 1) | |
| Real[:,2] | c2 | [p^2, p] coefficients of denominator polynomials (c2[i,1]*p^2 + c2[i,2]*p + 1) |
Outputs
| Type | Name | Default | Description |
|---|---|---|---|
| Real | alpha | Correction factor (replace p by alpha*p) |
Contents
| Name | Description |
|---|---|
| normalizationResidueprotected | Residue of correction factor computation |
| findIntervalprotected | Find interval for the root |
| solveOneNonlinearEquationprotected | Solve f(u) = 0; f(u_min) and f(u_max) must have different signs |