This example demonstrates how to use an RLC line model to connect a source to a load.
The model has four different loads. The loads sc_load
,
sc_load1
, sc_load2
, sc_load3
represent
short circuits R=0. The current that flows through the load depends
on the resistance, inductance and capacitance of the line.
The parameter R, L and C are such that at the nominal frequency fnom = 60 Hz the respective resistance and reactances are all equal to 10 Ω.
The lines used in this example have a T model (see BuildingSystems.Electrical.AC.ThreePhasesUnbalanced.Lines.TwoPortRLC). The equivalent impedance of the line on each phase is equal to
ZEQ = R/2 +jXL/2 + (R/2 +jXL/2)(-jXC)/ (R/2 +jXL/2 -jXC)
that in this case is equal to ZEQ = 15 + j5 Ω.
Given the equivalent impedance of each phase, and a voltage with an RMS value of 100 V produces a current equal to I = 6 - j2 A flowing through phase 1.
(1) Note:
The line model RLCLine_sc
is the same as RLCLine_1
but it uses
dynamic phasors.
(2) Note:
The line model RLCLine_2a
has a current that is different
from the one passing in RLCLine_1
because the series of two T
line models is different from the sum of the two separate line models.
(3) Note:
The line models RLCLine_3a
and RLCLine_3b
have currents that are
50% of the other lines because they are in parallel.