.BuildingSystems.Electrical.AC.ThreePhasesUnbalanced.Lines.Examples.ACLine_RLC

Information

This example demonstrates how to use an RLC line model to connect a source to a load.

The model has four different loads. The loads sc_load, sc_load1, sc_load2, sc_load3 represent short circuits R=0. The current that flows through the load depends on the resistance, inductance and capacitance of the line.

The parameter R, L and C are such that at the nominal frequency fnom = 60 Hz the respective resistance and reactances are all equal to 10 Ω.

The lines used in this example have a T model (see BuildingSystems.Electrical.AC.ThreePhasesUnbalanced.Lines.TwoPortRLC). The equivalent impedance of the line on each phase is equal to

ZEQ = R/2 +jXL/2 + (R/2 +jXL/2)(-jXC)/ (R/2 +jXL/2 -jXC)

that in this case is equal to ZEQ = 15 + j5 Ω.

Given the equivalent impedance of each phase, and a voltage with an RMS value of 100 V produces a current equal to I = 6 - j2 A flowing through phase 1.

Notes

(1) Note: The line model RLCLine_sc is the same as RLCLine_1 but it uses dynamic phasors.

(2) Note: The line model RLCLine_2a has a current that is different from the one passing in RLCLine_1 because the series of two T line models is different from the sum of the two separate line models.

(3) Note: The line models RLCLine_3a and RLCLine_3b have currents that are 50% of the other lines because they are in parallel.

Revisions


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